What is the value of (x + 2)(x  3) + 5, when x²  x  6 = 4 ?
A.) 2 B.) 1 C.) 1 D.) 2 E.) 3
Solve the equation x²  x  6 = 4, then substitute the value of x into (x + 2)(x  3) + 5.
x²  x  6 = 4 x²  x  2 = 0 {added 4 to each side} (x  2)(x + 1) = 0 {factored into two binomials} x  2 = 0 or x + 1 = 0 {set each factor equal to 0} x = 2 or x = 1 {added 2 and subtracted 1 from each side} If x = 2: (x + 2)(x  3) + 5 {given expression} = (2 + 2)(2  3) + 5 {substituted 2 for x} = 4(1) + 5 {added inside parentheses} = 4 + 5 {multiplied} = 1 {added} If x = 1: (x + 2)(x  3) + 5 {given expression} = (1 + 2)(1  3) = 5 {substituted 1 for x} = 1(4) + 5 {added inside parentheses} = 4 + 5 {multiplied} = 1 {added} C.) 1 Ask Algebra House Comments are closed.

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